1. The problem states we have a right triangle with an angle of 46° and sides labeled: adjacent side = 17, opposite side = x. 2. We want to find the correct trigonometric equation to solve for $x$. 3. Recall the definitions of trigonometric ratios for an angle $\theta$ in a right triangle: - $\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}$ - $\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$ - $\tan \theta = \frac{\text{opposite}}{\text{adjacent}}$ 4. Here, the angle is 46°, opposite side is $x$, adjacent side is 17. 5. Using the tangent ratio: $$\tan 46^\circ = \frac{x}{17}$$ 6. This matches the option: $\tan 46^\circ = \frac{x}{17}$. 7. Therefore, the correct equation to solve for $x$ is: $$\boxed{\tan 46^\circ = \frac{x}{17}}$$