1. **Solve for x in the right triangle with legs 25 and hypotenuse 56.** 2. **Solve for x in the scalene triangle with vertices O, H, and A (top-right corner).** --- ### Problem 1: Right Triangle 1. The problem states a right triangle with vertical leg 25, hypotenuse 56, and angle $x$ at the right angle vertex. 2. Use the sine function since sine relates the opposite side to the hypotenuse: $$\sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{25}{56}$$ 3. Calculate the ratio: $$\sin(x) = \frac{25}{56} \approx 0.4464$$ 4. Find $x$ by taking the inverse sine (arcsin): $$x = \sin^{-1}(0.4464)$$ 5. Using a calculator: $$x \approx 26.5^\circ$$ 6. Rounded to the nearest tenth of a degree: $$\boxed{26.5^\circ}$$ --- ### Problem 2: Scalene Triangle OHA 1. The problem does not provide explicit side lengths or angles for the scalene triangle OHA, so we cannot solve for $x$ without additional information. 2. If you provide side lengths or angle measures, we can apply the Law of Sines or Law of Cosines to find $x$. --- **Final answers:** 1. $x \approx 26.5^\circ$ (right triangle) 2. Insufficient information to solve for $x$ in the scalene triangle.