1. **State the problem:** Simplify the expression $\tan 40^\circ - \frac{\sin 40^\circ}{\cos 40^\circ}$.
2. **Recall the formulas:**
- $\tan \theta = \frac{\sin \theta}{\cos \theta}$.
- The expression involves $\tan 40^\circ$ and $\frac{\sin 40^\circ}{\cos 40^\circ}$ which are equivalent.
3. **Rewrite the expression using the formula:**
$$\tan 40^\circ - \frac{\sin 40^\circ}{\cos 40^\circ} = \frac{\sin 40^\circ}{\cos 40^\circ} - \frac{\sin 40^\circ}{\cos 40^\circ}$$
4. **Simplify the expression:**
$$\frac{\sin 40^\circ}{\cos 40^\circ} - \frac{\sin 40^\circ}{\cos 40^\circ} = 0$$
5. **Conclusion:** The expression simplifies to zero.
Tan Sin Cos 7A2A7B
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