1. **Problem 3:** A tree is supported by a guy wire anchored 7.0 m from the base of the tree. The angle between the wire and the ground is 60°. Find how far up the tree the wire reaches.
2. **Formula:** Use the sine function in a right triangle: $$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$ where the opposite side is the height up the tree, and the hypotenuse is the length of the wire.
3. **Given:**
- Distance from base (adjacent side) = 7.0 m
- Angle with ground $$\theta = 60^\circ$$
4. **Find the hypotenuse (length of wire):**
Use cosine since adjacent and hypotenuse are known:
$$\cos(60^\circ) = \frac{7.0}{\text{hypotenuse}}$$
5. Solve for hypotenuse:
$$\text{hypotenuse} = \frac{7.0}{\cos(60^\circ)}$$
$$= \frac{7.0}{0.5} = 14.0\text{ m}$$
6. **Find height up the tree (opposite side):**
$$\sin(60^\circ) = \frac{\text{height}}{14.0}$$
7. Solve for height:
$$\text{height} = 14.0 \times \sin(60^\circ)$$
$$= 14.0 \times 0.8660 = 12.1\text{ m}$$
---
8. **Problem 4:** A flagpole is 14.0 m high. The angle of elevation from Jon's position to the top is 63°. Find Jon's distance from the flagpole.
9. **Formula:** Use tangent function:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$
10. **Given:**
- Height (opposite) = 14.0 m
- Angle $$\theta = 63^\circ$$
11. Solve for adjacent (distance):
$$\tan(63^\circ) = \frac{14.0}{\text{distance}}$$
12. Rearrange:
$$\text{distance} = \frac{14.0}{\tan(63^\circ)}$$
13. Calculate:
$$\tan(63^\circ) \approx 1.9626$$
$$\text{distance} = \frac{14.0}{1.9626} = 7.1\text{ m}$$
**Final answers:**
- Problem 3: The wire reaches approximately **12.1 m** up the tree.
- Problem 4: Jon is approximately **7.1 m** from the flagpole.
Tree Flagpole Trig E6Cb06
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.