1. **State the problem:** We need to find the height of a tree that casts a shadow 21 meters long, given the angle of depression of the sun to the tree is 51°.
2. **Identify the right triangle and trigonometric function:** The shadow forms the adjacent side to the angle, and the height of the tree is the opposite side. We use the tangent function because \( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \).
3. **Write the formula:**
$$\tan(51^\circ) = \frac{\text{height}}{21}$$
4. **Solve for height:**
$$\text{height} = 21 \times \tan(51^\circ)$$
5. **Calculate the tangent:** Using a calculator,
$$\tan(51^\circ) \approx 1.2349$$
6. **Multiply to find height:**
$$\text{height} = 21 \times 1.2349 = 25.933$$
7. **Round to the nearest tenth:**
$$\text{height} \approx 25.9 \text{ meters}$$
**Final answer:** The height of the tree is approximately 25.9 meters.
Tree Height 9B127E
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