Subjects trigonometry

Tree Height B3Dd07

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1. **State the problem:** We are given the distance from a point P on the ground to the top of a tree as 6 m, and the angle of elevation from point P to the top of the tree is 59°. 2. **What we need to find:** The height of the tree. 3. **Relevant formula:** In a right triangle, the height of the tree corresponds to the side opposite the angle of elevation, and the distance given is the hypotenuse. We use the sine function: $$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$ where $\theta = 59^\circ$, opposite = height of the tree $h$, and hypotenuse = 6 m. 4. **Set up the equation:** $$\sin(59^\circ) = \frac{h}{6}$$ 5. **Solve for $h$:** $$h = 6 \times \sin(59^\circ)$$ 6. **Calculate $\sin(59^\circ)$:** Using a calculator, $\sin(59^\circ) \approx 0.8572$ 7. **Find $h$:** $$h = 6 \times 0.8572 = 5.1432$$ 8. **Round to 1 decimal place:** $$h \approx 5.1$$ **Final answer:** The height of the tree is approximately 5.1 meters.