1. **Problem statement:** Find the value of $x$ in the first right triangle where one angle is $68^\circ$, the side adjacent to this angle is 38, and the side opposite is $x$.
2. **Formula and rules:** In a right triangle, the tangent of an angle is the ratio of the opposite side to the adjacent side:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$
3. **Apply the formula:** Here, $\theta = 68^\circ$, opposite side = $x$, adjacent side = 38.
$$\tan(68^\circ) = \frac{x}{38}$$
4. **Solve for $x$:** Multiply both sides by 38:
$$x = 38 \times \tan(68^\circ)$$
5. **Calculate $\tan(68^\circ)$:** Using a calculator,
$$\tan(68^\circ) \approx 2.4751$$
6. **Find $x$:**
$$x = 38 \times 2.4751 = 94.0538$$
7. **Final answer:**
$$x \approx 94.05$$
This means the length of the side opposite the $68^\circ$ angle is approximately 94.05 units.
Triangle Side E04Bca
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