1. **State the problem:** Prove the identity $$\cos^4 \alpha - \sin^4 \alpha = \cos^2 \alpha - \sin^2 \alpha$$
2. **Use the difference of squares formula:** $$a^2 - b^2 = (a-b)(a+b)$$
3. Apply it to the left side:
$$\cos^4 \alpha - \sin^4 \alpha = (\cos^2 \alpha - \sin^2 \alpha)(\cos^2 \alpha + \sin^2 \alpha)$$
4. Use the Pythagorean identity:
$$\cos^2 \alpha + \sin^2 \alpha = 1$$
5. Substitute back:
$$= (\cos^2 \alpha - \sin^2 \alpha) \times 1 = \cos^2 \alpha - \sin^2 \alpha$$
6. **Conclusion:** The identity holds true.
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1. **State the problem:** Prove the identity $$\cos^2 \alpha (1 + \tan^2 \alpha) = 1$$
2. **Recall the identity:** $$1 + \tan^2 \alpha = \sec^2 \alpha$$
3. Substitute:
$$\cos^2 \alpha (\sec^2 \alpha) = \cos^2 \alpha \times \frac{1}{\cos^2 \alpha}$$
4. Simplify:
$$= \cancel{\cos^2 \alpha} \times \frac{1}{\cancel{\cos^2 \alpha}} = 1$$
5. **Conclusion:** The identity is proven.
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1. **State the problem:** Prove the identity $$ (1 + \tan^2 \alpha) \times \sin^2 \alpha = \tan^2 \alpha $$
2. Use the identity:
$$1 + \tan^2 \alpha = \sec^2 \alpha$$
3. Substitute:
$$\sec^2 \alpha \times \sin^2 \alpha$$
4. Express in terms of sine and cosine:
$$\frac{1}{\cos^2 \alpha} \times \sin^2 \alpha = \frac{\sin^2 \alpha}{\cos^2 \alpha}$$
5. Recognize the right side:
$$\tan^2 \alpha = \frac{\sin^2 \alpha}{\cos^2 \alpha}$$
6. **Conclusion:** The identity holds.
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1. **State the problem:** Prove the identity $$\sin \alpha \cos \alpha = \frac{\tan \alpha}{1 + \tan^2 \alpha}$$
2. Express $$\tan \alpha$$ as $$\frac{\sin \alpha}{\cos \alpha}$$:
$$\frac{\tan \alpha}{1 + \tan^2 \alpha} = \frac{\frac{\sin \alpha}{\cos \alpha}}{1 + \left(\frac{\sin \alpha}{\cos \alpha}\right)^2}$$
3. Simplify the denominator:
$$1 + \frac{\sin^2 \alpha}{\cos^2 \alpha} = \frac{\cos^2 \alpha + \sin^2 \alpha}{\cos^2 \alpha} = \frac{1}{\cos^2 \alpha}$$
4. Substitute back:
$$\frac{\frac{\sin \alpha}{\cos \alpha}}{\frac{1}{\cos^2 \alpha}} = \frac{\sin \alpha}{\cos \alpha} \times \cos^2 \alpha = \sin \alpha \cos \alpha$$
5. **Conclusion:** The identity is verified.
Trig Identities 31645F
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