1. **State the problem:** Verify if the identity $$\frac{\sin^2 \theta}{\cos \theta} + \frac{\cos^2 \theta}{\cos \theta} = \csc \theta$$ is true.
2. **Recall the Pythagorean identity:** $$\sin^2 \theta + \cos^2 \theta = 1$$.
3. **Simplify the left-hand side (LHS):**
$$\frac{\sin^2 \theta}{\cos \theta} + \frac{\cos^2 \theta}{\cos \theta} = \frac{\sin^2 \theta + \cos^2 \theta}{\cos \theta}$$
4. **Apply the Pythagorean identity:**
$$\frac{1}{\cos \theta} = \sec \theta$$
5. **Compare with the right-hand side (RHS):**
RHS is $$\csc \theta = \frac{1}{\sin \theta}$$
6. **Conclusion:**
Since $$\sec \theta \neq \csc \theta$$ in general, the identity is **false**.
**Final answer:** The statement is **False**.
Trig Identity Bc9Ab4
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