1. The problem asks to find the period of the waveform shown, which oscillates between 4 and -4 along the vertical axis and is plotted against $\theta$ on the horizontal axis. 2. The waveform appears sinusoidal, so the general form is $y = A \sin(B\theta)$ or $y = A \cos(B\theta)$, where $A$ is amplitude and $B$ affects the period. 3. The amplitude $A$ is the maximum absolute value of $y$, which is 4 here. 4. The period $T$ of a sinusoidal function $y = A \sin(B\theta)$ is given by the formula: $$T = \frac{2\pi}{B}$$ 5. From the graph, one full cycle starts at $\theta = 0$ and completes at $\theta = 2\pi$ (the waveform repeats every $2\pi$ units). 6. Therefore, the period $T = 2\pi$. 7. This means $B = 1$ since $T = \frac{2\pi}{B} = 2\pi$ implies $B=1$. Final answer: The period of the waveform is $2\pi$.