1. **State the problem:** We are given two points A(1, 11) and B(5, 4). We need to find: a) The vector $\overrightarrow{AB}$ as a column vector. b) The vector $3 \times \overrightarrow{AB}$ as a column vector. 2. **Formula and explanation:** The vector $\overrightarrow{AB}$ is found by subtracting the coordinates of point A from point B: $$\overrightarrow{AB} = \begin{pmatrix} x_B - x_A \\ y_B - y_A \end{pmatrix}$$ 3. **Calculate $\overrightarrow{AB}$:** $$\overrightarrow{AB} = \begin{pmatrix} 5 - 1 \\ 4 - 11 \end{pmatrix} = \begin{pmatrix} 4 \\ -7 \end{pmatrix}$$ 4. **Calculate $3 \times \overrightarrow{AB}$:** Multiply each component of $\overrightarrow{AB}$ by 3: $$3 \times \begin{pmatrix} 4 \\ -7 \end{pmatrix} = \begin{pmatrix} 3 \times 4 \\ 3 \times (-7) \end{pmatrix} = \begin{pmatrix} 12 \\ -21 \end{pmatrix}$$ **Final answers:** a) $\overrightarrow{AB} = \begin{pmatrix} 4 \\ -7 \end{pmatrix}$ b) $3 \times \overrightarrow{AB} = \begin{pmatrix} 12 \\ -21 \end{pmatrix}$