📘 graph theory
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Floyd Pred Explanation B39B37
1. **Énoncé du problème** :
L'algorithme de Floyd permet de calculer les plus courts chemins entre tous les couples de sommets $(i,j)$ dans un graphe simple sans circuit absorbant,
Construction Time Analysis 0119E3
1. **Stating the problem:**
We are asked to analyze the total construction time based on the minimum spanning tree (MST) found previously, considering collision durations and work
Net Coloring 6Ee2B6
1. **Problem statement:** We need to find the minimum number of colors required to color the faces of two nets (A and B) so that no two faces that touch share the same color.
2. **
Tree Proof 7616A0
1. **Problem:** Prove that if $G$ is a tree graph, then the number of vertices $|V(G)|$ equals the number of edges $|E(G)|$ plus 1.
2. **Formula and rules:** A tree is a connected
Minimum Spanning Tree 64828B
1. **Problem Statement:**
Determine a new network configuration by selecting cables (edges) to retain in the graph connecting districts a, b, c, d, e, f, g, h, i such that all dist
Triangle Free Cover 48D90F
1. **Problem Statement:** We want to construct a CNF Boolean expression $\phi_H$ for graph $H$ such that $\phi_H$ is True if and only if the assignment of truth values to variables
Cartesian Product Cycles Cd01A3
1. **Problem Statement:** We are given two cycles $\eta$ and $\eta'$ in a graph $G$ and asked to understand the Cartesian product graph $\hat{G} = \hat{G}(\eta, \eta')$ formed by t
Utilities Planarity 76098C
1. **Problem:** Can five houses be connected to two utilities without connections crossing? This is the classic "utilities problem" or the K_{3,3} bipartite graph problem.
2. **Exp
Cartesian Product Eea846
1. **Problem Statement:** Find the Cartesian product of the complete graph $K_3$ and the cycle graph $C_4$.
2. **Definitions:**
Roman Domination 02Fc5E
1. The problem is to understand the concept of extension edge Roman domination in graphs.
2. Roman domination in a graph is a function $f: V \to \{0,1,2\}$ assigning values to vert
Edge Roman Neighborhood 35Dac1
1. The problem is to formulate a title that links the concept of edge Roman domination with the concept of neighborhood in graph theory.
2. Edge Roman domination is a variant of do
Graph Edges F03B20
1. **Problem 1.1a:** Find all edges incident on vertex $v_1$.
Edges incident on $v_1$ are those connected to $v_1$. Given:
Prims Algorithm 959051
1. The problem is to find the Minimum Spanning Tree (MST) of a connected, weighted graph using Prim's algorithm.
2. Prim's algorithm starts with a single vertex and grows the MST b
Dijkstra Shortest Path 371A50
1. **Problem Statement:** Find the shortest path from vertex $a$ to vertex $z$ in the given graph using Dijkstra's algorithm.
2. **Graph Description:** Vertices: $a,b,c,d,e,f,g,z$.
Hamiltonian Circuits 82Fa27
1. **State the problem:** We need to show that the graphs in problems 31 and 32 do not have a Hamiltonian circuit. A Hamiltonian circuit is a cycle that visits every vertex exactly
Euler Circuit 11Bb83
1. **Problem Statement:** Determine if the given graphs have an Euler circuit based on their vertex degrees.
2. **Key Concept:** A graph has an Euler circuit if and only if it is c
Graph Paths Trails Walks 88A645
1. **Problem Statement:**
We have a graph with nodes $a$, $b$, and $c$ and edges:
Loai Do Thi Chuyen Bay 89700B
1. **Nêu bài toán:**
Cho đồ thị hướng biểu diễn các chuyến bay giữa các thành phố Boston, Newark, Miami, Detroit, Washington với số chuyến bay cụ thể.
Graf Terhubung 6Bc599
1. Soal 1: Diberikan himpunan simpul $V = \{A, B, C, D\}$ dan himpunan sisi $E = \{\{A,B\}, \{A,C\}, \{B,D\}, \{C,D\}\}$.
2. Tentukan derajat setiap simpul. Derajat simpul adalah j
Matrik Bersisian 0191Ae
1. Masalah: Tentukan matriks bersisian (incidence matrix) untuk graf dengan 4 simpul dan 6 sisi.
2. Matriks bersisian adalah matriks yang menunjukkan hubungan antara simpul dan sis
Seymour Conjecture 761Ff3
1. The problem is to investigate Seymour's Second Neighborhood Conjecture, which states that in any finite directed graph, there exists a vertex whose second out-neighborhood is at